Homework Answers
// V stands for OR(disjunction),
//^ stands for AND(conjuction),
//' stand for NOT(negation),
//--> stands for NOT(A) OR B (implication)
//Evaluate expression
// (A V B) --> (B' --> A)
// !(A || B) || (B'' || A)
// !(A || B) || (A || B)
#include<iostream>
#include<iomanip>
#include<string>
#include<sstream>
using namespace std;
bool conjuction(bool a, bool b); // a && b
bool disjunction(bool a, bool b); // a || b
bool negation(bool a); // !a
bool implication(bool a, bool b); //!a || b
bool equivalence(bool a, bool b); // (!a || b) && (a ||
!b)
int main()
{
bool x[4] = {0,0,1,1};
bool y[4] = {0,1,0,1};
bool z[4];
// V stands for OR(disjunction),
//^ stands for AND(conjuction),
//' stand for NOT(negation),
//--> stands for NOT(A) OR B (implication)
//Evaluate expression
// (A V B) --> (B' --> A)
// !(A || B) || (B'' || A)
// !(A || B) || (A || B)
cout<<"Truth table\n";
cout<<"| A | B |Result|\n";
cout<<"-----------------------\n";
for(int i=0;i<4;i++)
{
z[i] = disjunction(x[i],y[i]); // (A || B)
z[i] = disjunction(negation(z[i]),z[i]); //!(A || B) || (A ||
B)
cout<<"| ";
if(x[i] == 0)
cout<<"False |";
else
cout<<"True |";
if(y[i] == 0)
cout<<"False |";
else
cout<<"True |";
if(z[i] == 0)
cout<<"False |";
else
cout<<"True |\n";
}
}
bool conjuction(bool a, bool b) // a && b
{
if(a==1 && b==1)
return 1;
return 0;
}
bool disjunction(bool a, bool b) // a || b
{
if(a==0 && b==0)
return 0;
return 1;
}
bool negation(bool a) // !a
{
if(a==1)
return 0;
return 1;
}
bool implication(bool a, bool b) //!a || b
{
if(a==1 && b==0)
return 0;
return 1;
}
bool equivalence(bool a, bool b) // (!a || b) && (a ||
!b)
{
if (a == b)
return 1;
return 0;
}
output:-
Prove:-
Add Answer to:
c++
please include comments
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BTNode(){}
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