Question

Conceptual Question 17.9 (Figure 1) shows the light intensity on a viewing screen behind a single slit of width a. The light's wavelength is lambda.Part A Is lambda < a, lambda = a, lambda > a. or is it not possible to tell? Drag the terms on the left to the appropriate blanks on the right to complete the sentences. w = 2L lambda/a [The width of the central maximum in the intensity pattern fora single slit is given by ] w = 2aL/lambda [ if lambda > = a than a w will be equal to or 2L.] greater than [ It is obvious that w << 2L, hence lambda is______ a. less than equal to) w = 2a lambda /L

please help me

Answer 1

if the ratio of a/$\lambda$ grows the peaks become narower

since in picture it seems $\lambda$<a

central maxima width w=2y=2L$\lambda$/a

if $\lambda$>>a

than width then w is more than 2L

if w<< 2L means mean $\lambda$<<a