Given: The time taken = 23 seconds
Initial concentration of HBr = [HBr]0 = 0.550 M
concentration after 23s = [HBr]t = 0.457 M
The reaction is
2HBr(g) ---> H2(g) + Br2(g)
Rate of reaction =
Rate of reaction =
Therefore rate of reaction = -1/2 (0.550 - 0.457) / 23 = 0.00404 M s-1
Therefore the average rate of reaction = 0.00404 M s-1
b) The volume = 1.50 L
time = 15 seconds
Rate = d[Br2] /dt = 0.00404 M s-1
d[Br2] = 0.00404 X 15 = 0.0606 M
Moles = Molarity X volume in litres = 0.0606 M X 1.5 L = 0.0909 moles
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