1) P(winning the jackpot) =(1/38C2)*(!/52) =1/36556
2) P(At least 2 have same) =1-P(none have same) =1-365P32/36532 =0.7533
3)
a)
probability = | P(X>=1)= | 1-P(X<=0)= | 1-∑x=0x-1 (nCx)px(1−p)(n-x) = | 0.984375 |
b)
probability = | P(X>=3)= | 1-P(X<=2)= | 1-∑x=0x-1 (nCx)px(1−p)(n-x) = | 0.656250 |
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