Question

In Madagascar, where snow is in short supply, children sled down steep dirt hills on wood and cardboard planks. Two boys want to figure out how much faster one sled is compared to the other. The coefficient of kinetic friction between a dirt surface and wood is uk = 0.158; the coefficient of kinetic friction between a dirt surface and cardboard is uk = 0.390. If they both start from rest at the top of the hill, which has a slope of 50.4 degrees with respect to horizontal and vertical height of 75.9 m, what will be the difference in speed between the two sledders when they get to the bottom of the hill? You can assume that both boys have the same mass of 40.8 kg (would it matter if they had different masses?) Image size: s ML Max Please enter a numerical answer below. Accepted formats are numbers or "e" based scientific notation e.g. 0.23, -2, 126, 5.23e-8 Enter answer here 3.68 m/s 3.68 m/s X Your Answer

Answer 1

Sin 50.4 = 75.4 75.4 SD-4 S: 75.9 sin 50.4 98.50 m UN " Fangsine Img mgsino - yong coso = ma a-gsmo - Mg Coro Na mg coso mgcole when 4k = 0.158 a = 9.88m 50.4-0.158x9.8 Losso.4 a> 6.56 m2 Using v² u² - 2as v2-0 = 2*6.52 x 98.37 - Jax 6.56 x 98.50 - 35.94 m/s when 4 = 0.390 a= 9.8 &nso.4 -0.158x9.8x cosso.4 a -> 5.114 mys? - Using v ax 5.116x98.50 = 31.74 V S "X78.50 – 31.74 difference - 35-94- 31.947 4.199 Scanned with CamScanner