Question

I need help on part G!!!!!

Blocks A and B are on a frictionless horizontal surface. Block A is to the left of block B. Both blocks are initially at rest. Block A has a mass of 2.1 kg and B has a mass of 1.5 kg. Block A is struck from the left with a hammer. The average force of this impact is 210 N and lasts for 0.09 seconds. Block A slides to the right, strikes and sticks to block B. The two blocks then slide to the right together. They then reach a rough surface which has a coefficient of kinetic friction of 0.27.

A) Sketch diagrams of the situation before and after the blocks collide as well as when the blocks are sliding on the rough surface. Label all variables.

B) List all known quantities.

C) Draw a free body diagram for the blocks as they slide on the rough surface. Treat the 2 blocks as one object.

D) Use impulse to determine the speed of block A after the hammer strikes it.

E) What is the speed of the 2 blocks after they stick together (before they reach the rough surface)?

F) What is the kinetic energy of the 2 blocks after they stick together?

G) How far do the blocks slide on the rough surface before they stop?

Answer 1

Soin A2.1kg, mg= 1.5kg Fova = 210N at 0.09 sec UK = 0.27 (G) After sto After striking with hammen, momentum of block A is given by, PA = 0 Fong ot = 2104009 PA = 18.9 kg mis -et Kebe u be the velouty of both blocks after collision doom Conservahon o momenturn. PA = (ma+mB) u u= 18.9 (2.) +1-51 = 5.25 mis rough surface. Let blocks slide a deetance on from Conservation of Energy: KE og blows = cuork done by dochon. I (MAIMB) e 2 = 4k (Marmo) gd > d= 4² = (5.25)? 2469 240.27*9.8 d=5.208 m