Question

450 4.0 m/s 30 g 12.0 m/s Ó 20g

(Figure 1) shows a collision between three balls of clay. The three hit simultaneously and stick together. Assume that m = 55 g and v = 2.1 m/s .

Part A- What is the speed of the resulting blob of clay?

Part B- What is the movement direction of the resulting blob of clay?

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Answer #1

By momentum conservation A 58[ 4 com {s} – 4-sinus i) + (30) (-2.11) + (20)(21) = (55+30+20) Ū 92.5631 - 115.563) = lost U= 0

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