Question

A box with mass M=10 kg is on the back of a trailer and it has the coefficient of friction μ=0.2 with the back of the trailer. a) What is the maximum possible acceleration a=? of the truck such that the box does not slip on the back of the truck? b) If the truck moves with acceleration A=100 m/s such that the box slips on the back of the truck, with that acceleration will the box move on the back of the tuck? c) When the truck moves with acceleration A=100 m/s the box moves distance d=1 m relative to the truck before it fall down. What is the velocity of the box relative to the ground when it falls down?

Answer 1

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mora a) when maaf , box will not slip. }= pra ) @ 9 max. acc. amax = 0.2x9.8 : 1,96 mks? (6) Az 100 mls² ma=ma-ung at a = 100-1196 a=98.04 m/s² (c) A = 100 mish, d= lm, a=98.04 m/s² Asi u² u²= aad .. of be?= 2X98.04x1 [: uzo] =) Vzly mis. Hence velocity of block relative to ground u= 14 mb.

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