Option B is correct
This will list the ids of nodes that link to both nodes with id=3 and the node with id = 4
Consider the following table definitions: create table node (node_id integer primary key, node_color varchar(10)); create table...
create table candidate ( cand_id varchar(12) primary key, -- cand_id name varchar(40) -- cand_nm ); create table contributor ( contbr_id integer primary key, name varchar(40), -- contbr_nm city varchar(40), -- contbr_city state varchar(40), -- contbr_st zip varchar(20), -- contbr_zip employer varchar(60), -- contbr_employer occupation varchar(40) -- contbr_occupation ); create table contribution ( contb_id integer primary key, cand_id varchar(12), --...
CREATE TABLE DEPT ( DEPTNO INTEGER NOT NULL, DNAME VARCHAR(14), LOC VARCHAR(13), PRIMARY KEY (DEPTNO)); INSERT INTO DEPT VALUES (10,'SPORTS','NEW YORK'); INSERT INTO DEPT VALUES (20,'HOME','DALLAS'); INSERT INTO DEPT VALUES (30,'OUTDOOR','CHICAGO'); INSERT INTO DEPT VALUES (40,'CLOTHING','BOSTON'); CREATE TABLE EMP ( EMPNO INTEGER NOT NULL, ENAME VARCHAR(10), JOB VARCHAR(9), MGR INTEGER, SAL FLOAT, COMM FLOAT, DEPTNO INTEGER NOT NULL, FOREIGN KEY (DEPTNO) REFERENCES DEPT (DEPTNO), FOREIGN KEY (MGR) REFERENCES EMP(EMPNO), PRIMARY KEY (EMPNO)); INSERT INTO EMP VALUES (7839,'KING','PRESIDENT',NULL, 5000,NULL,10); INSERT INTO...
This is database system concept. 1.Find the ids of instructors who are also students using a set operation. Assume that a person is identified by her or his id. So, if the same id appears in both instructor and student, then that person is both an instructor and a student. Remember: set operation means union, intersect or set difference. 2.Find the ids of instructors who are also students using the set membership operator. 3.Find the ids of instructors who are...
Given: Create table Book ( Book_id integer, Book_title varchar(50), Author varchar(50), Publish_date date, Type varchar(30), Edition number, Quantity number, Primary key (Book_id) ); insert into Book values (1,'The Old Man and the Sea','Hemingway' ,date '1978-1-1','hardcopy',3,2); insert into Book values (2,'The Old Man and the Sea','Hemingway' ,date '1979-1-1','hardcopy',4,1); insert into Book values (3,'The Old Man and the Sea','Hemingway' ,date '1980-1-1', 'hardcopy',5,10); insert into Book values (4,'A Farewell to Arms','Hemingway' ,date '1986-1-1','hardcopy',2,18); insert into Book values (5,'For Whom the Bell Tolls','Hemingway' ,date...
-- Schema definition create table Customer ( cid smallint not null, name varchar(20), city varchar(15), constraint customer_pk primary key (cid) ); create table Club ( club varchar(15) not null, desc varchar(50), constraint club_pk primary key (club) ); create table Member ( club varchar(15) not null, cid smallint not null, constraint member_pk primary key (club, cid), constraint mem_fk_club foreign key (club) references Club, constraint mem_fk_cust...
rider_student Column Data Type Description student_id integer the primary key first_name varchar(25) student first name last_name varchar(25) student last name major_id integer the ID of the student's major; a foreign key for the major_id in the rider_major table rider_major Column Data Type Description major_id integer the primary key major_name varchar(50) student first name major_description varchar(100) student last name Use the Tables above to answer the questions. Questions: 1. Write a SQL statement to add a student record to the rider_student...
CREATE TABLE customer ( id INTEGER PRIMARY KEY, customer_name TEXT, contact_number TEXT ); CREATE TABLE supplier ( id INTEGER PRIMARY KEY, supplier_name TEXT UNIQUE, contact_number TEXT ); CREATE TABLE product ( id INTEGER PRIMARY KEY, supplier_id INTEGER REFERENCES supplier(id), product_name TEXT, product_price INTEGER, UNIQUE(supplier_id, product_name) ); CREATE TABLE purchase ( id INTEGER PRIMARY KEY, customer_id INTEGER REFERENCES customer(id), purchase_date REAL, store_id INTEGER REFERENCES store(id) );...
Given the schema, write a query and subquery to do the following: CREATE TABLE Majors major VARCHAR(12), description VARCHAR, PRIMARY KEY (major) ); CREATE TABLE Course ( courseMajor VARCHAR(12), courseNo VARCHAR(6), credits INTEGER NOT NULL, enroll_limit INTEGER, PRIMARY KEY(courseNo, courseMajor), FOREIGN KEY (courseMajor) REFERENCES Majors (major) CREATE TABLE Tracks trackMajor VARCHAR(12), trackCode VARCHAR(10), title VARCHAR, PRIMARY KEY(trackMajor, trackCode), FOREIGN KEY (trackMajor) REFERENCES Majors(major) CREATE TABLE Student ( SID CHAR(8), sName VARCHAR(30), studentMajor VARCHAR(12), trackCode VARCHAR(10), PRIMARY KEY(SID), FOREIGN KEY (studentMajor,...
Database concepts Find the names and ids of the students who have taken at most one course in the Spring 2010 semester. Notice, at most one means one or zero. So, the answer should include students who did not take any course during that semester The data: create table classroom (building varchar(15), room_number varchar(7), capacity numeric(4,0), primary key (building, room_number) ); create table department (dept_name varchar(20), building varchar(15), budget numeric(12,2) check (budget > 0), primary key (dept_name) ); create...
/* I am executing following SQL statement for the below code but I am getting error. Pls, upload screenshot after running it. SQL Statement: SELECT OfferNo, CourseNo FROM Offering WHERE OfferTerm = 'Sum' AND OfferYear = 2012 AND FacSSN IS NULL; */ CREATE TABLE STUDENT( StdSSN INT NOT NULL PRIMARY KEY, StdFName VARCHAR2(50), StdLName VARCHAR2(50), StdCity VARCHAR2(50), StdState VARCHAR2(2), StdZip VARCHAR2(10), StdMajor VARCHAR2(15), StdYear VARCHAR2(20) ); CREATE TABLE FACULTY( FacSSN INTEGER NOT NULL PRIMARY KEY, FacFName VARCHAR(50), FacLName VARCHAR(50), FacCity...