A transverse wave on a string is given by the formula D(x,t) = 0.15 sin(4.0x - 43.0t). where D and z are in m and t is in s
Part A
At t = 7.0 x 10 2s. what is the transverse displacement of the point on the string where z-0.45m?
Express your answer using two significant figures.
D(0.45m, 7.0 × 10-2S) =
Part B
At t = 7.0 × 10 2s. what is the (transverse) velocity of the point on the string where x = 0.45m?
(A)
Displacememt on the string is
D(0.5m , 7*10-2 s) = 0.1*sin(3.6(0.5) - 41(7.4*10-2) )
= 0.1sin(-1.234)
= 0.1*-0.0215
= -0.022 m
(B)
the velocity of the string is ,
D (x,t) /t = 0.10(-41)cos(3.6*x - 41*t)
D (0.45 , 7*10-2) /t = -4.1 cos(3.6*0.45 - 4.1*7*10-2)
= -4.1cos(1.62 - 0.287)
= -4.09 m/s
A transverse wave on a string is given by the formula D(x,t) = 0.15 sin(4.0x - 43.0t). where D and z are in m and t is in s
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