The equation describing a transverse wave on a string is y(x,t)=( 2.50mm )sin[( 168s?1 )t?( 42.1m?1...
The equation describing a transverse wave on a string is
y(x,t)=( 2.50mm )sin[( 168s?1
)t?( 42.1m?1 )x].
A. Find the wavelength of this wave.
B. Find the frequency of this wave.
C. Find the amplitude of this wave.
D. Find the speed of motion of the wave.
E. Find the direction of motion of the wave.
F. Find the transverse displacement of a point on the string when t = 0.160s and at a position x = 0.140m.
Homework Answers
comparing with y = Asin(wt - kx)
k = 2*pi/lambda= 42.1
wavelength = lambda = 2*3.14/42.1 = 0.15 m
w = 2*pi*f = 168
f = 26.75 Hz
A)
lambda = 0.15 m
B)f = 26.75 Hz
C) A = 2.5mm
D) v = w/k = (168)/42.1 = 3.99 m/s = 4
m/s
E) +x axis
F) y = 2.5mmsin((168*0.16)-(42.1*0.14)) = 2.11
mm
Add Answer to:
The equation describing a transverse wave on a string is
y(x,t)=( 2.50mm )sin[( 168s?1
)t?( 42.1m?1...
Given: The equation describing a transverse wave on a string is y(x,t)=( 4.00 mm )sin[( 162...
Given:
The equation describing a transverse wave on a string is
y(x,t)=( 4.00 mm )sin[( 162 s^−1 )t−( 42.5 m^−1 )x].
λ = 0.148 m
f= 25.8 Hz
A= 4mm
v= 3.81 m/s
Find the transverse displacement of a point on the string when t-0.180 s and at a position 0.145 m. Submit Previous Answers Request Answer
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Given:
The equation describing a transverse wave on a string is
y(x,t)=( 4.00 mm )sin[( 162 s^−1 )t−( 42.5 m^−1 )x].
λ = 0.148 m
f= 25.8 Hz
A= 4mm
v= 3.81 m/s
Find the transverse displacement of a point on the string when t-0.180 s and at a position 0.145 m. Submit Previous Answers Request Answer
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a) Show that this equation can be written as:
b) Find your amplitude, wave number, angular frequency and indicate
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c) Find the propagation speed, wavelength, frequency, and wave
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d) Find and draw the wave profile between x=0 and x=90cm, in
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e)Write the equation that defines the motion of the point x =
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