A beam of length 7m and mass 200kg is suspended from two ropes as show. Find the tension in each rope.
ANSWER
Weight of the beam
200 kg(9.8 m/s²) = 1960 N
Let T1 and T2 be the rope tensions.
forces in the vertical direction must add to zero
T1cos30 + T2cos60 - 1960 = 0
forces in the horizontal direction must add to zero
T1sin30 - T2sin60 = 0
T1 = T2sin60/sin30
substitute into the first equation
T2sin60cos30/sin30 + T2cos60 - 1960 = 0
T2(sin60cos30/sin20 + cos60) = 1960
T2 = 727.85 N
T1 = T2sin60/sin30
T1 = 727.85sin60/sin30
T1 = 1260.67 N
Regards!!!
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