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Consider the circuit in the figure below, taking a = 6.00 V, L = 6.40 mh, and R = 8.20 1. 100 (a) What is the inductive time

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Solution - Parta Inductive time constant T=L L = 6.40 mH = 6.40X1034 R = 81200 Then I - 6.Yoxlo SH -3 8.200 = 0.17X10 3 = OrZPart(d) - o -ott It) = I.C) -2] etc - 1- I t= -7 ln (1-52] & It) = 80%= 0.8 I. mo Then _ - 0.77 ms x ln [1-0.8] = 1,24 ms

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