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You repeatedly throw a dice. 1. Compute the probability of the following events. Write these events precisely using other eve

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Answer #1

The event of throwing a die is independent ( second throw is independent of first )

P[ A 6 ] = 1/6

P[ A non 6 ] = 5/6

g) P[ the first two rolls are 6 ] = P[ A 6 ]*P[ A 6 ]

P[ the first two rolls are 6 ] = (1/6)*(1/6)

P[ the first two rolls are 6 ] = 1/36

h) P[ the first double in second and third rolls ] = P[ A non 6 ]*P[ A 6 ]*P[ A 6 ]

P[ the first double in second and third rolls ] = (5/6)*(1/6)*(1/6)

P[ the first double in second and third rolls ] = 5/216

i)

P[ the first double in third and fourth rolls ] = P[ A non 6 ]*P[ A non 6 ]*P[ A 6 ]*P[ A 6 ]

P[ the first double in third and fourth rolls ] = (5/6)*(5/6)*(1/6)*(1/6)

P[ the first double in third and fourth rolls ] = 25/1296

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