Calculate ΔG∘rxn and E∘cell at 25∘C for a redox reaction with n = 3 that has an equilibrium constant of K = 4.7×10−2. You may want to reference (Page) section 18.5 while completing this problem.
Part A
Express your answer using two significant figures.
Part B
Express your answer using two significant figures.
after considering the condition that answer must be in two significant figure
Calculate ΔG∘rxn and E∘cell at 25∘C for a redox reaction with n = 3 that has...
Calculate ΔG∘rxn and E∘cell for a redox reaction with n = 2 that has an equilibrium constant of K = 4.9×10−2. You may want to reference (Pages 861 - 865) Section 19.5 while completing this problem. Part A Express your answer using two significant figures. ΔG∘rxn = kJ Part B Express your answer using two significant figures. E∘cell = V
Calculate ΔG∘rxn and E∘cell at 25∘C for a redox reaction with n = 4 that has an equilibrium constant of K = 5.9×10−2. Part A Express your answer using two significant figures. Part B Express your answer using two significant figures.
Calculate ΔG∘rxn and E∘cell at 25∘C for a redox reaction with n = 4 that has an equilibrium constant of K = 5.9×10-2. Part A Express your answer using two significant figures. Part B Express your answer using two significant figures.
Calculate ΔG∘rxn and E∘cell at 25∘C for a redox reaction with n = 4 that has an equilibrium constant of K = 5.0×10−2.
Calculate ΔG∘rxn and E∘cell for a redox reaction with n = 1 that has an equilibrium constant of K = 25. (Temperature is 298 K.
2a. Calculate ΔG∘rxn at 25∘C for a redox reaction with n = 4 that has an equilibrium constant of K = 5.1×10−2. 2b. Calculate E∘cell at 25∘C for a redox reaction with n = 4 that has an equilibrium constant of K = 5.1×10−2.
Please show work. Thanks so much Calculate ΔG∘rxn and E∘cell for a redox reaction with n = 2 that has an equilibrium constant of K = 21.
2Ca(s)+O2(g) → 2CaO(s) ΔH∘rxn= -1269.8 kJ; ΔS∘rxn= -364.6 J/K You may want to reference (Pages 706 - 709) section 17.5 while completing this problem. Part A Calculate the free energy change for the reaction at 15 ∘C. Express your answer using four significant figures.
The equilibrium constant for the following reaction is K = 6 × 10-16 at 25°C Cus(s) + 2 H3O_ (aq) Cu2 (aq) + H38(aq) + 2 H20(1) You may want to reference (Page) Section 15.1 while completing this problem. Part A What is the concentration of Cu2 (aq)when excess CuS(s) reaches equilibrium with a solution in which [H30" =0.28 Ml and [H2S] = 7x10-2 M? Express the answer using two significant figures [Cu2+ ] = Request Answer
A reaction has ΔH∘rxn= -115 kJ and ΔS∘rxn= 319 J/K . You may want to reference (Page) section 17.4 while completing this problem. At what temperature is the change in entropy for the reaction equal to the change in entropy for the surroundings? Express your answer in kelvins.