Question

Automobile traffic passes a point ? on a road of width ? feet with an average rate of ? vehicles per second. Although the arrival of automobiles is irregular, traffic engineers have found that the average waiting time ? until there is a gap in traffic of at least ? seconds is approximately ?=???? seconds. A pedestrian walking at a speed of 3.3 ft/s requires ?=?3.3 s to cross the road. Therefore, the average time the pedestrian will have to wait before crossing is ?(?,?)=(?3.3)???/3.3 s. What is the pedestrian's average waiting time if ?=23 ft and ?=0.2 vehicle per second? (Use decimal notation. Give your answer to two decimal places.)

Automobile traffic passes a point P on a road of width w feet with an average rate of R vehicles per second. Although the arrival of automobiles is irregular, traffic engineers have found that the average waiting time T until there is a gap in traffic of at least t seconds is approximately T = teRt seconds. A pedestrian walking at a speed of 3.3 ft/s requires t = us to cross the road. Therefore, the average time the pedestrian will have to wait before crossing is f(w, R) = () ewR13.3 s. What is the pedestrian's average waiting time if w = 23 ft and R = 0.2 vehicle per second? (Use decimal notation. Give your answer to two decimal places.)

​​​​​​​

Answer 1