Question

A laser beam in air is incident on a liquid at an angle of 35.0 ∘...

A laser beam in air is incident on a liquid at an angle of 35.0 ∘ with respect to the normal. The laser beam's angle in the liquid is 24.0 What is the liquids index of refraction?

Can someone please show me how to do this one? Thanks!

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Answer #1

By snell's law, refractive index= (sin 'i') / (sin 'r') where 'i' is angle of incidence and 'r' is the angle of refraction which are 39 and 27 degrees respectively.

refractive index = (sin 35) / (sin 24)
= 1.4101

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