The decomposition reaction: 2N2O5 (g) --> 4 NO2 (g) + O2 (g) has a rate constant kr = 0.1217 hr^–1 A reaction vessel of fixed volume is first evacuated and then filled with N2O5 to an initial pressure of 1.00 atm. The decomposition reaction is then initiated. (a) What are the partial pressures of each of the three gases in the reaction vessel when the total pressure is 1.30 atm? (b) At what time would you expect the total pressure to be 1.30 atm?
The decomposition reaction: 2N2O5 (g) --> 4 NO2 (g) + O2 (g) has a rate constant...
6) The rate constant for the first-order decomposition of N2O5 in the reaction 2N2O5(g) → 4NO2(g) + O2(g) is k=3.38 x 10-5 s-1 at 25°C. What is the half-life of N2O5? What will be the total pressure, initially 88.3 kPa for the pure N2O5 vapour, (a) 10 s, (b) 10 minutes after initiation of the reaction?
The decomposition of N2O5 in solution in carbon tetrachloride proceeds via the reaction: 2N2O5 (soln) → 4NO2 (soln) + O2 (soln) The reaction is first order and has a rate constant of 4.82 x 10-3 s-1 at 64 oC. The reaction is initiated with 0.058 mol in a 1.25 L vessel. What is the half-life of the reaction?
At a particular temperature, Kp-0.39 for the reaction below. N204(g) 2 NO2(g) (a) A flask containing only N204 at an initial pressure of 4.8 atm is allowed to reach equilibrium. Calculate the equilibrium partial pressures of the gases. N2O4 NO2 atm (b) A flask containing only NO2 at an initial pressure of 9.6 atm is allowed to reach equilibrium. Calculate the equilibrium partial pressures of the gases. No2 (e) From your answers to parts (e) and (b), does it matter...
The decomposition of N2O5 is described by the following equation. 2N2O5(g) → 4NO2(g) + O2(g) If the rate constant is 2.50 × 10−4 s−1, what is the half-life of this reaction?
The decomposition of N2O5 proceeds according to the following equation: 2 N2O5 (g) -> 4 NO2 (g) + O2 (g) If the rate of decomposition of N2O5 at a particular instant in a reaction vessel is 5.3 x 10-5 M/s, what is the rate of appearance of NO2?
The first-order rate constant for the decomposition of N2O5, 2N2O5(g)→4NO2(g)+O2(g) at 70∘C is 6.82×10−3 s−1. Suppose we start with 2.40×10−2 mol of N2O5(g) in a volume of 2.1 L. a) How many moles of N2O5 will remain after 7.0 min? b) How many minutes will it take for the quantity of N2O5 to drop to 1.6×10−2 mol?
Consider the rate of decomposition: 2 N2O5(g) → 4NO2(g) + O2(g). The rate of reaction will be dependent on: A. [N2O5] B. [NO2] C. [O2] D. [NO2] and [O2]
1. At a particular temperature, K = 2.50 for the reaction: SO2 (g) + NO2 (g) ⇄ SO3 (g) + NO (g). If all four gases had initial concentrations of 1.00 M, calculate the equilibrium concentrations of SO2. 2. At a particular temperature, Kp = 0.25 for the reaction: N2O4 (g) ⇄ 2 NO2 (g). A flask containing only N2O4 at an initial pressure of 4.5 atm is allowed to reach equilibrium. a. Calculate the equilibrium partial pressure of N2O4....
The first-order rate constant for the decomposition of N2O5, 2N2O5(g)→4NO2(g)+O2(g) at 70∘C is 6.82×10−3 s−1. Suppose we start with 2.30×10−2 mol of N2O5(g) in a volume of 1.5 L . a. How many moles of N2O5 will remain after 6 min ? b. How many minutes will it take for the quantity of N2O5 to drop to 1.9×10−2 mol ? c. What is the half-life of N2O5 at 70∘C?
The first-order rate constant for the decomposition of N2O5, 2N2O5(g)→4NO2(g)+O2(g) at 70∘C is 6.82×10−3 s−1. Suppose we start with 2.00×10−2 mol of N2O5(g) in a volume of 2.0 L . How many moles of N2O5 will remain after 7.0 min? How many minutes will it take for the quantity of N2O5 to drop to 1.6×10−2 mol? What is the half-life of N2O5 at 70∘C?