Question

The reaction of hydrogen peroxide with iodine, H2O2(aq)+I2(aq)?OH?(aq)+HIO(aq) is first order in H2O2 and first order...

The reaction of hydrogen peroxide with iodine,

H2O2(aq)+I2(aq)?OH?(aq)+HIO(aq)

is first order in H2O2 and first order in I2 . If the concentration of H2O2 was increased by half and the concentration of I2 was quadrupled, by what factor would the reaction rate increase?

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Answer #1

ate = k(H2O2)^1(I2)^1
assume H2O2 was 1 and I2 was 1. Rate would be k(1)(1) = 1
Now, H2O2 increased by half and quadruple I2.
Rate k(1.5)(4) = 6

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