The value of an observation is 0.028; the value of the mean is 0.062. The value of the deviation is
Given that, the value of an observation is 0.028 and the value of the mean is 0.062
We want to find, the value of the deviation
Deviation = observation value - mean = 0.028 - 0.062 = -0.034
=> Deviation = -0.034
The value of an observation is 0.028; the value of the mean is 0.062. The value...
The value of an observation is 216; the value of the mean is 221.3. The value of the deviation is _______________.
Consider a distribution with a mean of 15 and a standard deviation of 3. If an observation from the distribution has a z-score of -2, what is the value? Consider a distribution with a mean of 15 and a standard deviation of 3. If an observation from the distribution has a z-score of -2, what is the value?
5. Roll the die another 40 times and calculate the value of x. Sample Mean Observation (= second observation of X): 6. Now write your two X values (one from question 2 and one from question 5). Comment on the values. 7. The random variable X represents the outcome of a single roll of the die, and the random variable X represents the sample mean of 40 rolls of the die. Use the Central Limit Theorem, and the values in...
A random variable is normally distributed with a mean of 30 and a standard deviation of 5. If an observation is randomly selected from the distribution, a. What value will be exceeded 15% of the time? b. What value will be exceeded 80% of the time? c. Determine two values of which the smaller has 5% of the values below it and the larger has 5% of the values above it. d. What value will 20% of the observations be...
21) (8 points) The Z-score for an observation from a Normal distribution is -0.4. For the following, choose the one answer that is most appropriate. a. The observation is Left of the mean Right of the mean Very close to the mean It cannot be determined without knowing the mean and standard deviation b. Observations smaller than this value comprise The majority of the distribution Slightly less than half of the values in the distribution Unusually large observations It cannot...
When parking a car in a downtown parking lot, drivers pay according to the number of hours or fraction thereof. The probability distribution of the number of hours cars are parked has been estimated as follows: X12345678P(X)0.2130.1170.120.0850.0620.0280.0230.352A. Mean = _______ B. Standard Deviation = _______ The cost of parking is 3.25 dollars per hour. Calculate the mean and standard deviation of the amount of revenue each car generates A. Mean = _______ B. Standard Deviation = _______
What is the value for Kif[N2] -0.025, [Hz] -0.0013, and (NH2] = 0.028 for the reaction N2 (g) + 3H2(g) + 2NH3 (8) 7.45 1.2E-3 7.1E-8 1.47 8.6E2
2. A single observation is to be used to test the null hypothesis that the mean waiting time between tremors recorded at a seismological station (the mean of an exponential population) is θ-10 hours against the alternative that θ 10 hours. If the null hypothesis is to be rejected if and only if the observed value is less than 8 or greater than 12, find (a) the probability of type I error; (b) the probabilities of type II errors when...
on Known: P-Value Approach Determine the p o or a hypothesis best for the mean population standard deviation Question What is the p value of a two-tailed one-mean hypothesis test, with a test statistic of 2 = -1.59? (Do not round your answer; compute your answer using a value from the table below.) 2 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 -1.8 0.036 0.035 0.034 0.034 0.033 0.032 0.031 0.031 0.030 0.029 -1.7 0.045 0.014 0.043 0.042...
Delta IBM Jan-83 0.04 0.027 Feb-83 0.027 0.01 Mar-83 -0.016 0.028 Apr-83 -0.043 0.15 May-83 -0.045 -0.041 Jun-83 0.012 0.081 Jul-83 -0.259 0.001 Aug-83 0.08 0.001 Sep-83 0.041 0.062 Oct-83 0.039 -0.001 Nov-83 0.12 -0.066 Dec-83 -0.028 0.039 Jan-84 -0.013 -0.065 Feb-84 -0.117 -0.026 Mar-84 0.065 0.034 Apr-84 -0.085 -0.002 May-84 -0.07 -0.044 Jun-84 -0.012 -0.019 Jul-84 0.045 0.047 Aug-84 0.04 0.127 Sep-84 0.008 0.004 Oct-84 0.161 0.012 Nov-84 -0.026 -0.023 Dec-84 0.156 0.011 Jan-85 -0.01 0.108 Feb-85 0.087 -0.009...