Question

We have a square where each side is 2cm. At the top-left corner, there is a charge of -3uc. What does the charge need to be at the bottom left corner and the top right corner so that the electric field at the bottom right corner is zero? An electron is released from rest in a uniform electric field. The electron accelerates vertically upward, traveling 4.50m in the first 3.00 mu s after it is released. What is the magnitude of the electric field? In what direction is the electric field? A massless insulating rod of length D = 3dm has positive and negative charges of + 100 uC and -100 uC, fixed at each end of the rod. It is angled 30-degrees from horizontal and then placed in a uniform electric field of strength E = 10 N/c that is directed in the vertical direction. If the positive charge is on the right-upper end of the rod, and the negative rod is at the lower-left side: what is the torque experienced by the rod? And .... What is the angular acceleration...?

Answer 1

Diagram net 23 The charges q, d q, should be positive (as the charge q, is negative) for the above situation. In the figure. Enet 2,3 is the net field of the charges of q2 and%- The net field of three charges at right bottom comer is zero. net E, E2 +E,0 (cos45°-sin 45)+(-i)+-0 91 22 V2

Here, a is the side length of the cube. 91 242 91 2/2 72 d3 Therefore, 2/2 -+1.06 OC