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2) 4 charges are fixed to the corners of a square of side 0.53 cm. Charge 1 of -1°C is fixed to the top left corner. Charge 2

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Answer -240 A-TRC o -*-> ----To- --- -- ad L TED liec ° 3mc a -4MC . Fig. O fig- o Given, a = 0.53 cm. ( AB = BC=CD=0A) qA =Magnitude of EA 1 X 10 16A) = 9x109 x 1x100 (6.375 x1022) 604x108 Nl Direction is towards OA since it is negative Magnitude oUTICO Magnitude of fio illa le = 9x109 x 3x106 .. (0.375 x 10?)? 19.3x108 wilc (Rowards do Positive charge) From fig. ® FA anResultant electric field; F S Fit kept 2 E1-E2 COSO - (19.2.)(32) + 2x19.2 x32400590.) xrom = 37.32 x 108 Nic Directions de tVB - I 96 = 9x109 x (+23106) 4716 (BO) (0.315x10%) 15 +6 = -4.8 x 10 V : V : 1 Qc . 9x10°x (-4X 70) 4 TI EO (co) 70.315 xro-?+ вр. (BD) 3 с р (CD) J + t axro9x102 | -IX-2 0. 53 , TX-4 0.75 = x 3 2 0. 53 + 10-2 + ) 2x-4 - 0.53 + -2x3 - 0.75 +38-4 0.53

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