An aqueous solution containing 17.3 g of an unknown molecular (nonelectrolyte) compound in 102.0 g of...
Homework Answers
Quantity of solute dissolved in 1kg of solvent = 17.3*1000/102= 169.6g
Freezing point depression constant for water =
1.86 degrees/mol
Given depression point = 1.6 degrees
Molar mass of solute = 169.6*1.86/1.6 = 197.16g/mol
Molar mass of unknown compound = 197.16g/mol
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