An aqueous solution containing 15.0 g of an unknown molecular (nonelectrolyte) compound in 100.5 g of water has a freezing point of -1.9 ∘C. Calculate the molar mass of the unknown compound. I am stumped because I am not given Kf??
Kf = 1.860C/m
Tf = 0-(-1.9) = 1.90C
i = 1 for non electrolyte
Tf = i*Kf*m
1.9 = 1*1.86*m
m = 1.9/1.86 = 1.0215m
molality = W*1000/G.M.M.Weight of solvent in g
1.0215 = 15*1000/G.M.M*100.5
G.M.M = 15*1000/(1.0215*100.5) = 146g/mole
molar mass of unknown compound = 146g/mole >>>>answer
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