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onnected in series. 4. Two capacitors with capacitances of 1.0 and 0.50 1F, respectively, are connected in The system is conn
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Answer #1

(1)

the resultant capacitance will be

C=c1×c2/(c1+c2)

=0.33 microfarad

the resultant charge comes out to be

(q = CV) = 0.33 x 10^-6×100

q=0.33×10^-4 C
since the charge is same in series.

q1=33.3 micro-coulamb

q2=33.3 micro-coulamb

(2)

The capacitors are in parallel,

(a) equivalent capacitance

C=c1+c2

C=10+15

C=25 microfarad

(b) voltage is same in parallel,

q1=CV

q1=10×10^-6*6

q1=6×10^-5 C

q1=60 micro-coulamb

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