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4 1 -1] 3. (6 points) Given the 3 is an eigenvalue of the matrix A= 2 5 -2 , find a basis for the corresponding 1 1 2 eigensp

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Solution. Gieeni eigenvalue = 3 Now we need to find corresponding eigenrecter Sole A-3I 2 5-3 -2 | LII 2-3 . ri 1 -17 2 2 -2

тг 7 гол ооо | 7 | ao Lбоо L? лечеz = о Эх = -— Here two variable are free ги - 1 + о L+ 2 = = 1 А е тама, geu veeter useumi

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