Question

Question 4 (Could be considered as Quiz 3- 4.5 pts). An armature-controlled DC motor of figure below has the following characteristics: Ra=1.2 ohms, L. - 0, KT = 0.06 N-m/A (motor-torque constant), K = 0.06 V-s/rad (back-emf constant). It has maximum speed of 500 rad's with a maximum current of 2 A. We suppose that all possible frictions are represented in friction torque Tr=0.012N-m. R: armature resistance, 2 La armature inductance, H is : armature current, A is: field current, A ca : applied armature voltage, 4 constant back emf, V 0 : angular displacement of the motor shaft, rad T:motor torque find: Q4.1. The maximum output torque, Tmax (1.5pts) Q4.2. The maximum mechanical output power, Pmax (1.5pts) Q4.3. The maximum armature voltage, e. (1.5pts)

Answer 1

Given Razlan Katz 0,06 Nam A T = 0.012 Non Dette > 0.06 Vstraal Wmar z 500 rad Is Imaxe 2 A La zo ca).maximum Torque Tmax - z Ky X Imax - TF 0,06 X 2 - 0.012 Tmax = 0.108 Nm (6) maximum pouver : Prozay - Womax X Imax = 500 x 0.108 Prsax = 54 cc) maximum armature voltage Ea= Imaxx Ra tke Wmax 1.2 x 2 + 0.06 7 500 6oz 32.4V Sdanned with humo.Scanner