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2- Knowing that a 0.5-mm gap exists between the rods shown below when the temperature is 20 °C, determine: (a) The temperatur

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given, &-0.5 mm Ty=20°c @ 6 = -150 mpa S = 20TL, & d)2 -0.5 = ((23x10x300) + 1821625) JOT) . 0.5 = 0.0114 CAT) LOT = 43,86 No(6 Corresponding exact length of to stainless sted sod - AL= 2₂x₂ (AT) = 250 x 18 x 106 x 43.86 L₂ - ₂ = 0.19737 1 = 250 + 01

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