Question

Chapter 2, Reserve Problem 036 At a temperature of 54°F, a 0.12 in. gap exists between the ends of the two bars shown. Bar (1) is an aluminum alloy (a = 12.4 x 10-6/°F] and bar (2) is stainless steel [a = 8.3 x 10-6/F]. The supports at A and C are rigid. Determine the lowest temperature at which the two bars contact each other. Assume L1 = 45 in., L2 = 63 in. (1) Answer: Final temperature = the tolerance is +/-2%

Answer 1

Given, Au = 12.4 XI061°F steel= 8.3 X10-6/F %3D Gap (s)= 0.12 in L= 45 in L2= 63in Led 'T' the Jouest temperature at which be the bars each 0ther. Contact. Elongadion in Aluminum + Elongation in steel = Gap 0.12 AAl + Astecel => => L,AL(T-54)+L2teel (T-54) = 0.12 => 45x 12.4 X106 (T-54)+ 63%8.3X10(7-54)= 0.12 => (T- 54) 4SX12.4+63Xa3]X10-6 = 0.12 0.12 1ot6 > (7-54) ( 1080-9) = => T-54 165.018 F