Question

In the figure four particles are fixed along an x axis, separated by distances d -4.70 cm. The charges are q_1 - +2e, q_2 - -e, q_3 - +e, and q_4 - +4e, with e - 1.60 times 10^-15 C. What is he value of the net electrostatic force on (a) particle 1 and (b) particle 2 due to the other particles? (a) Number ________________ units (b) Number ________________ unit

Answer 1

a )

given

d = 4.7 cm

q₁ = 2 e , q₂ = - e , q₃ = + e , q₄ = + 4 e

E₂ = - k q / d²

E₂ = - 9 X 10⁹ X 1.6 X 10^-19 / 0.047²

E₂ = - 6.51 X 10^-7 N/C

E₃ = k q / d²

E₃ = 9 X 10⁹ X 1.6 X 10^-19 / 0.047²

E₃ = 6.51 X 10^-7 N/C

E₄ = 4 k q / d²

E₄ = 4 X 9 X 10⁹ X 2 X 1.6 X 10^-19 / 0.047²

E₄ = 2.6 X 10^-6 N/C

E = - 6.51 X 10^-7 N/C+ 6.51 X 10^-7 N/C + 2.6 X 10^-6 N/C

E = 2.6 X 10^-6 N/C

b )

E₁ = 2 k q / d²

E₁ = 2 X 9 X 10⁹ X 2 X 1.6 X 10^-19 / 0.047²

E₁ = 1.3 X 10^-6 N/C

E₃ = k q / d²

E₃ = 9 X 10⁹ X 2 X 1.6 X 10^-19 / 0.047²

E₃ = 6.51 X 10^-7 N/C

E₄ = 4 k q / d²

E₄ = 4 X 9 X 10⁹ X 2 X 1.6 X 10^-19 / 0.047²

E₄ = 2.6 X 10^-6 N/C

E = 1.3 X 10^-6 + 6.51 X 10^-7 + 2.6 X 10^-6 N/C

E = 4.551 X 10^-6 N/C