given
a = 6.1 cm = 0.061 m
q1 = 8.41 nC ,
q2 = - 19.2 nC ,
q3 = 19.2 nC ,
q4 = - 8.41 nC
r = a / 1.414
r = 0.061 / 1.414
r = 0.0431 m
E1 = k q1 / r2
= 9 X 109 X 8.41 X 10-9 / 0.04312
= 40745.9 N/C
E3 = k q3 / r2
= 9 X 109 X 19.2 X 10-9 / 0.04312
= 93022.75 N/C
E13 = 93022.75 - 40745.9
= 52276.85 N/C
E2 = k q2 / r2
= - 9 X 109 X 19.2 X 10-9 / 0.04312
= - 93022.75 N/C
E4 = k q4 / r2
= - 9 X 109 X 8.41 X 10-9 / 0.04312
= - 40745.9 N/C
E24 = 52276.85 N/C
E = ( (E24)2 + (E24)2 )1/2
E = ( (52276.85)2 + (52276.85)2 )1/2
E = ( 0 i + 52276.85 j ) N/C
In the figure the four particles form a square of edge length a = 6.10 cm...
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