a)
following table is |xi + yj|
x | |||||
-1 | 0 | 1 | |||
y | -3 | 4 | 3 | 2 | |
0 | 1 | 0 | 1 | ||
3 | 2 | 3 | 4 | ||
sum | 20 |
hence 20c = 1
c = 1/20
b)
joint probability mass function
` | x | ||||
-1 | 0 | 1 | |||
y | -3 | 0.2 | 0.15 | 0.1 | 0.45 |
0 | 0.05 | 0 | 0.05 | 0.1 | |
3 | 0.1 | 0.15 | 0.2 | 0.45 | |
0.35 | 0.3 | 0.35 | 1 |
y | p(y) |
-3 | 0.45 |
0 | 0.1 |
3 | 0.45 |
c)
x | P(x) |
-1 | 0.35 |
0 | 0.3 |
1 | 0.35 |
d)
P(Y < X)
= P(-1,-3)+P(0,-3)+P(1,-3) + P(0,1) {P(X =x, Y =y) = P(x,y)}
= 0.2 + 0.15 + 0.1 + 0.05
=0.5
e)
P(Y = X)
= P(0,0) = 0
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