1-a)
Following table shows the marginal pdfs of X and Y:
X | |||||
2 | 3 | 4 | P(Y=y) | ||
-1 | 0.1 | 0.2 | 0.05 | 0.35 | |
Y | 0 | 0.27 | 0.1 | 0.15 | 0.52 |
1 | 0 | 0.03 | 0.1 | 0.13 | |
P(X=x) | 0.37 | 0.33 | 0.3 | 1 |
b)
c)
So the required probability is
d)
Following table shows the calculations:
e)
Following table shows the calculations:
So we have
f)
Since P(Y=-1) = 0.35, P(X=2) = 0.37 and P(X=2,Y=-1) = 0.1 so P(X=2, Y=-1) is not equal to P(X=2)*P(Y=-1). Therefore X and Y are not independent.
Questionl The random variable X and Y have the following joint probability mass function: 0.14 0.27...
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