Question

Solve for all currents in this circuit. Find the voltage difference Vb-Va.

Solve for all currents in this circuit. Find the voltage difference AVAB = VB - VA A ww 3.9 Q 6.7 Q + 12 V 1.2Q 9.0 V 9.8 Q ww ww

Answer 1

Now, as we know that according to Kivenoff's voltage Hope awo (KVL). the nel moltage aeross any loop. OV A Vioop or also, acur ding to Kirchoft's junction law. current in coming = current outgoing at at a point the same pornt.

» Drawing the given ciro agram Solving the problem. 3.9.52 A A is is 0.72 N - 1. 22 13 (loop2) 9-82 to be új is a la >> Assuming the currents in the branches law at junction A. > > Kirchoff's junction Applying (at the junction) Current incoming = current outgoing G+ t'ga in - o >> Now, applying Horchoff's voltage floop law in loop O (+12V) + (-4x3.4) + (-sx1.2) + (-ix98) = 0 12 -4 (3.914.8) = box1-2 inn (137) = 12X120B 12-

12 - 12x1-2 = (137) son gearranging i = :- ) 12- lz (1.2) 13-7 loop@ => Again, applying Keychaffes voltage floop law in [+ls(6-7)] -(4.0) +- iz (1.2) = 0 . 13 (6.7) = 9 - Cz (1-2) is = q- iz (1-2) 6.7. - >> putting @ so in equation © (it is = 6) + (2 12 - 1 (1-2) - 13.7 9- (1.2) = 6.7 - L2(1-2) 2 (2 + 12 13-7 - . L2 (1-2) 13.7 77 (12/7) + (1/2) = 4/1+ "%+ + "%67) 2.2192 = 1z (1.2667) iz = 2.2192. - 1.752 A 1-2667 12 - LR (1.2) - 12 - (1-752) (1-2) 13.7 13.7 putting is in equation 0 Lin 12- Ez (1-2) a - 13.7 1; = 0723 4

ß using o = 6-ci = 1:752 -0.723 4 - 1.0294 c So, . the currents in the are circuit Alimeter li = 0.723 4 in= 1.752 A (- 1.029 A - finding A NAB from A to B. along the circuit writing the voltage VA + 13 (617) - 9.00 = VE -2-1057 V Ve - VA = (1-029) (6-7) -9.0V = A Van = -2.1 r. Answer