In an experiment about pumpkin yield we tested 3 varieties. Each
variety was assigned to 4 randomly selected plots.
SS variety = 253.85
SS error = 108.09
Average for variety A is 29.2. Average for variety B is 31.7.
Do you reject the null hypothesis that varieties A and B have the
same mean yield?
What is the LSD to test for differences in yield between varieties?
SS | df | MS | F | p-value | |
Variety | 253.85 | 2 | 126.925 | 3.522759 | 0.163201 |
Error | 108.09 | 3 | 36.03 | ||
Total | 361.94 | 5 |
Do you reject the null hypothesis that varieties A and B have the same mean yield?
No, we fail to reject the null hypothesis.
What is the LSD to test for differences in yield between varieties?
LSD = t*sqrt(MSerror(1/n1 + 1/n2) = 3.18*sqrt(36.03(1/3+1/4) = 14.59
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In an experiment about pumpkin yield we tested 3 varieties. Each variety was assigned to 4...
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