Question

#3. 2 Consider the following results for two samples randomly taken from two populations. AWN Sample Size Sample Mean 7 Sample Standard Deviation Sample A Sample B 20 25 28 22 9 a. Determine the degrees of freedom for the t distribution. 10 b. At 95% confidence, what is the margin of error? 11 c. Develop a 95% confidence interval for the difference between the two population means.

Answer 1

Given 220 W28 L325. 2= 25 H2 = 22 8 2= 6. freedom @ Determine the degree of for the t-distribution, → degree of freedom: D + 02-2. - 20+25-2 la f = 431 AL 85 are confidence , what is the margin of error margin of error - tout sexi-x2 where te= t-statistic determined by 95°10 confidance interval. - ter 2.0166 5 CR-] = Standard error sett. #ta] where nisi?+02 3² nito2 2005)2 + 25 (6)2 20+25 , 81.14. =

15 = 31.14 31.14% tl 120 25 167 .:. Margin of error - 2.02X1167. - 3.38. margin of error = 3.38.1 0 95% confidance interval for the difference between the two population mean becomes f(x1 - *2) - margin of (2-6) + margio of) error nor (628-22) – 3:38, (28-22)+3.38). ( 6 - 3.38 + 6+ 3.38) (61998).