As we know that to neutrilize HCl we will need 1:1 mole ration of NaOH.
So concn.of HCl×Vol of HCl=concn.of NaOH×Vol of NaOH.
We are not given the initial concentration of HCl in the question so we will assume ot to be 0.1M forthe ease of calculation.
So 0.1×10=0.170×Volume of NaOH
Volume.of NaOH will be 5.88 ml if initial conc of HCl is 0.1M.
The flask shown here contains 10.0 mL of HCI and a few drops of phenolphthalein indicator....
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