(5a - 10)/(6a - 12)
= (5(a - 2))/(6(a - 2))
= (5/6)*((a-2)/(a-2))
= (5/6)*1
= 5/6
implies (5a - 10)/(6a - 12) = 5/6
(2x2 - 5x -12)/(x2 - 5x + 4)
First let us factorize both numerator and denominator
Factorizing 2x2 - 5x - 12 we get
2x2 - 5x - 12
= 2x2 - 8x + 3x - 12
= 2x(x - 4) + 3(x - 4)
= (x - 4)(2x + 3)
implies 2x2 - 5x - 12 = (x - 4)(2x + 3)
Factorizing x2 - 5x + 4 we get
x2 - 5x + 4
= x2 - x - 4x + 4
= x(x - 1) - 4(x - 1)
= (x - 1)(x - 4)
implies x2 - 5x + 4 = (x - 1)(x - 4)
Now
(2x2 - 5x - 12)/(x2 - 5x + 4)
= ((x - 4)(2x + 3))/((x - 1)(x - 4))
= (2x + 3)/(x - 1)
implies (2x2 - 5x - 12)/(x2 - 5x + 4) = (2x + 3)/(x - 1)
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