Question

1. (9 points) Balance the following reactions: H3PO4(1) + HCIE) C4H3 + O2 CO2 + H2O PC15(s) + H2O LizNs) LiOH) + NH3(g) C3H12

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Answer #1

1)

a)

C_{4}H_{8} +6 O_{2} \to 4 CO_{2} (g) +4 H_{2}O

b)

PCl_{5} (s) +4 H_{2}O (l) \to H_{3}PO_{4} (l) +5 HCl (g)

c)

Li_{3}N (s) +3 H_{2}O (l) \to 3 LiOH (l) + NH_{3} (g)

d)

C_{5}H_{12} +8 O_{2} \to 5 CO_{2} (g) +6 H_{2}O

2)

a)

Al_{2}(CO_{3})_{3} (s) +3 H_{2}SO_{4} (aq) \to Al_{2}(SO_{4})_{3} (s) +3 H_{2}O (l) + 3CO_{2} (g)

b)

6 F_{2} (g) +2 Al_{2}O_{3} (s) \to 4 AlF_{3} (s) + 3 O_{2} (g)

c)

3 NiCl_{2} (aq) +2 Na_{3}PO_{4} (aq) \to Ni_{3}(PO_{4})_{2} (s) +6 NaCl (aq)

3)

Combustion of n- heptane is

C_{7}H_{16} (l) + 11 O_{2} (g) \to 7 CO_{2} (g) +8 H_{2}O (g)

Molar mass of n-heptane is 7*12+16*1 = 100 g/mol

100 g of n-heptane on Combustion gives 7*44 g of Carbon dioxide.

How many grams of n-heptane on Combustion gives 225 g of carbon dioxide.

= 225 g * 100 g/7 *44 g

= 73.05 g

4)

Hydrolysis of calcium carbide is

CaC_{2} (s) + 2H_{2}O (l) \to C_{2}H_{2} (g) + Ca(OH)_{2} (s)

Molar mass of Calcium carbide is 1*40+2*12 = 64 g/mol

Molar mass of acetylene = 2*12+2*1 = 26 g/mol

64 g of calcium carbide on Hydrolysis gives 26 g of acetylene.

75000 g of calcium carbide on hydrolysis gives ? g of acetylene.

= 75000 g * 26 g/64 g

= 30468.75 g

= 30.5 Kg

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