Question

You have the following info: C3H8(t) + O2(g) → CO2(g) + H2O(g) AHrx = -2044 kJ Given 3.97 kg of C3H8(9) react and the gas produced from the reaction is collected in a 5.00 L container at 298 K. Molar masses: C3H8 = 44.09 g/mol, H2O = 18.02 g/mol, CO2 = 40.02 g/mol a) What is the heat of the reaction given the conditions described (i.e. what is Gnx)? b) is the reaction exothermic or endothermic? c) Is heat a product or reactant for this reaction? d) Assuming that the reaction works perfectly, what pressure of gas should be collected in the container at 298 K?

Answer 1

C 3 H 8 (1) + 02 (8) C02 (9) +H48) Alloxn=-2044 kJ The balanced chemical equation - C3 Hg (1) +502 (9) 3C0₂(8) + 4H2016) Houn-204455/ amount of C3 H8 (8) ix 3.97 kg. mol. 2 3.97 x 103 qm I 3.97x10² gm 44.09 gm/mol 90.04 mol . ( The heat of the reaction given in the condition 88 Iron = 2044890.04 kJ 2 - 184041.76 ks. 16 A Hoxn '18 negative, so the reaction is exothermic. ☺ for a exothermie reaction heat is written in the product side. so, neat is product for this reaction. @ Is the reaction works perfectly. from 90.04 molot C33 (8) We will get (90.04x3) no or 270 . 12 mol of CO2(g) and 10.84х4) mol or 360.16 mol of H2O (9) Total Pressure P = Peoz & PH2O Panitial pressure 1 partial press me of for Co2 of L0260 volume (W)-SL - 270.12 mol PV = NRT 2) P2 NRT R=0.082 Latm molk. > 270-12X0.082x298 H20 m) T = 298K dd The - 1320.13 atm

for H₂O. V=5L n = 360.16 mol R = 0.082 Latm motu T 2 29810 The Phao = 360.16 x 0. 082x298 tim T 2 1760 17 atm . Total pressure P= Pcot Pro = (1320 13 + 1760-17) atm.