Question

for python, i have some ideas on how to approach it but not sure. any suggestions help! thank you.

4 is sorted (head) This function takes a single parameter, which is a list, and returns True or False, indicating whether or not the values in the list are sorted. Note that duplicates may exist in the list; these count as being in order. An empty list should return True. I 5 list sum(head) This function takes a single parameter, which is a list, where all of the values are numeric. It returns the sum of all of the values stored in the list. An empty list should return zero.

Answer 1

#list initialization
numList = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

#method to check if list is sorted or not
def is_sorted(head):
list1 = head[:]
list1.sort()
if list1 == head:
return True
else:
return False

#method to find the sum of the list
def list_sum(head):
total = 0
for i in range(len(head)):
total = total + head[i]
return total

#check if list is sorted
if is_sorted(numList):
print("The list is sorted")
else:
print("The list is not sorted")
  
#display the sum of the list
print("The sum of the list is:",list_sum(numList))

The screenshot of the above source code is given below:

#list initialization numList = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] #method to check if list is sorted or not def is_sorted(head): list1 = head[:] list1.sort() if list1 == head: return True else: return false #method to find the sum of the list def list_sum(head): total = 0 for i in range(len(head)): total = total + head[i] return total #check if list is sorted if is_sorted(numList): print("The list is sorted") else: print("The list is not sorted") #display the sum of the list print("The sum of the list is:",list_sum(numList))

OUTPUT:

The list is sorted
The sum of the list is: 55