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* A quality Control expert wants to estimate the Proportion os defective components that are being manufactured by his Compan
math   Statistics-And-Probability   
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Answer #1

we know that p = 20 / 300 = 0.067

The ME = Zcritical * SQRT(p * q/n).

Squaring and solving, n = (Zc/ME)2 * p * q

Here ME = 2.5% = 0.025, p = 0.067, q = 0.933

The Zc at \alpha = 0.01 is 2.576

Therefore n = (2.576 / 0.025)2 * 0.067 * 0.933 = 663.69

Therefore n = 664 (Rounding to the nearest Integer)

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