solubility = 5.91 *10^-4 in 100 ml = 5.91*1000/100 in one litre = 5.91*10^-3 g = x (say)
NowKsp ( Zn3(PO4)2 = (solubility of Zn)^3 * (solubility of PO4) ^2 = x3*x2 =x5 = (5.91*10^-3)5
= 7.210*10^-12
Need help The solubility of Zinc phosphate, Zn_3(PO_4)_2 is 5.91 times 10^-6 g in 100 ml...
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Use activities to calculate the molar solubility of Zn(OH)_2 (Ksp=3 times 10^-16) in 0.01 M KCI.
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The solubility of magnesium chloride at 20 degree C is 54.9 g/100 mL of water. That of magnesium iodide is 148.0 g/100 mL. Using this information, do you expect magnesium fluoride to be more or less soluble than magnesium bromide? Explain your reasoning. What are two hazards are associated with using a centrifuge? In this experiment, why is it important to dispose of all waste chemicals as heavy metal hazardous waste? Complete and balance the following precipitation equations. Write the...
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