Question

The solubility of PbBr_2 is 0.427 g per 100 mL of solution at 25 degree C. Determine the value of the solubility product constant for this strong electrolyte. Lead(II) bromide does not react with water. 5.4 times 10^-4 6.3 times 10^-6 1.6 times 10^-6 3.1 times 10^-6 2.7 times 10^-4 Calculate the maximum concentration (in M) of silver ions (Ag^+) in a solution that contains 0.025 M of CO^2-_3. The K_sp of Ag_2 CO_3 is 8.1 times 10^-12. 8.1 times 10^-12 1.4 times 10^-6 3.2 times 10^-10 1.8 times 10^-5 2.8 times 10^-6

Answer 1

To calculate solubility product (Kp) from solubility (x), write the ionic equation of the chemical reaction, and show concentration of total ions in solution (cations and anions) Kip-CationAnion Ionic equation of PbBr, in water; From equation (1); Concentration of anions is twice the concentration of cations in ionic product of PbBr, The concentration of PbBr, in 100 ml solution in mole, is calculated as follows: Conversion of mass of PbBr, into moles of PbBr, is, as follows: mass of PbBr, x - moles of PbBr, molecular masss of PbBr molecular mass of PbBr, - 367g.mol mass of PbBr, given - 0.427g 0.427 gx 0.001163 mol 367 g mol Hence, 1 L of solution contain PbBr, as, follows: 0.001163 In 1L solution moles of PbBI,contains Pb2+ and Br x1000 100 = 0.01 163M

The Kp for solubility of PbBr, is, as follows: Substitute the value of x into equation (3), which is shown as follows; -4(0.01163) 6.323x106 The Solubility product of PbBr, after rounding off is 6.3x10

To calculate solubility (x) from solubility product (Kp), write the ionic equation of the chemical reaction, and show concentration of total ions in solution (cations and anions) Ionic equation of Ag,CO3 in water; 23(5 From equation (1); Concentration of cations is twice the concentration of anions in ionic product of Ag,CO The concentration of Ag as x and concentration of co3 is given as 0.025, where x is the solubility of Ag,CO3. From equation (2); -12 The K,p for solubility of Ag.СО, is 8.1 x 10 Substitute the value of K, and the concentration of CO into equation (3) to get the concentration of Ag asx, which is shown as follows;

2x] [0.025] 8.1x102 8.1 x10-12 4 x0.025 =9810-6M Since the concentration of Ag is 2x,therefore: Ag+ = 2x 9x10-6M -1.8x10 M