The 20 lb bar is released from rest in the horizontal position 1 and falls to...

Question

Question

The 20 lb bar is released from rest in the horizontal position 1 and falls to position 2. In addition to the force exerted on

Answer 1

Answer #1

12 Net torque a 20x2 + 50 = dost lb. also = I4 - 20x 4² x 90= 26.672 x = 3.37 rad/s² angular displacment o= 40 - 40XT = 0.7 r

Answer 2

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