Question

Problem 8.41 A 2.0 kg rock is released from rest at the surface of a pond 1.8 m deep. As the rock falls, a constant upward force of 4.4 N is exerted on it by water resistance. Let y = 0 be at the bottom of the pond. ✓ Correo Part F Calculate the Express you U =

Answer 1

Sat 8. m=2kg Hi = 1.8m F--4.4N Panett H₂ = 0.50m Growitational potentialenergy - mg (Hır – Ha) U= 2x9.81(1.8-0.5) = 2x9.81x1.3 TUS 25.5065) Part G Initial veloce uzomie Q=-=-4.4 - - 2.2 m/s2 As we know relation. V²-02=2as {S = H, H₂ = 1:8-0.5=1.3} V?= 2x-2.2 X 1:3 12 -5.72 m/s2 As we know, - Kinetic Energy (K.E)=1/mv2 K.E=-1x2x572 KE 25.7257 Hence.