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3. Use the Maximum/Minimum Principles to deduce that the solution u of the problem D.E. u = kuv 0 < x < 1, t > 0. B.C. u(0,0)

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solution Given that t = KL-cx 02 720 uxx = I ux u(x,) - vit) tit) WXX = x xt1t) (titu- *(TTD x(x) T(U) 1xT X ) divide doy (afrit ) = cz sindrė Prat o=ucht) = cg sirp te P²kt C2+0. Sinput >0 sin presin S pre anu (pan] =) u (%;t)= c2 sinna e-prkt an

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