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If the volume of the original sample in Part A (P1 = 702 torr , V1...

If the volume of the original sample in Part A (P1 = 702 torr , V1 = 32.0 L ) changes to 62.0 L , without a change in the temperature or moles of gas molecules, what is the new pressure, P2? Express your answer with the appropriate units. P2 =

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Answer #1

We have in Boyle law

P1V1 = P2V2

P1 = 702 torr

V1 = 32L

V2 = 62L

So, 702 torr x 32 L = P2 x 62 L

P2 = 362.3torr = 0.476atm

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