Question

A sample of ideal gas at room temperature occupies a volume of 31.0 L at a pressure of 862 torr. If the pressure changes to 4310 torr, with no change in the temperature or moles of gas, what is the new volume, V2? Express your answer with the appropriate units. ► View Avallable Hint(s) V2 = 6.20 L Submit Previous Answers Correct Part B If the volume of the original sample in Part A (P1 - 862 torr. Vi = 31.0L ) changes to 50.0 L, without a change in the temperature or moles of gas molecules, what is the new pressure, P? Express your answer with the appropriate units. View Available Hint(s) PANA ROO ? Value Units

Answer 1

® Initial roleume (vi)=312 Pressure (P.) = 800 862 torr finial pressure (P2) = 4310 torr Final volume = V2 say, . From ideal gas love, we have S pi v = P2 V2 [ No change in temperature, : No = PNI or moles of gast P2 862 X 31 4310 6. 20L! - = 6.20 L TV2 = 6, 20L -

2 P = 862 torr, N=312 V2 = 50 L P2 = ? from om ideal ideal gas gas law, law, we - Pivi " have piri = P2 V2 P2 = V2 862 x 31 50 - = 534, 44 torr [P2 = * 34. 44 torr Initial temperature (T) = 26c = (20 + 273) K = 293k Initial volume (V) = 1.71x103 L Final temperature (72) = 73°c = (2+3+73) K = 346k . From ideal gas law, we have V [V2 = Final volume] .; V2 = V1 T2 = 1.77x10° x 346 2 T 293 IVO = 2.09 kis 1 2090 + 2.09x10°2 - € Ti= 20c 23 V = 1.77X10² L N2 = 3.54 x10² L T2=? from ideal gas law, we have v = V₂ . Tz = vž T : 3.54x10? x 0223 c reato 1.77x103 Ti

..T2 = 586k = (586-273) c = 313°c 1. Tz = 313°C m = 2.10 moles: N = 47 L mg = (2.10 – 0.500) = 4.6 miles - Final rolume = 2 From ideal gas law we have n2 NL nevis 106 x 47 ni = 35.80 L - 2.10 36 L. 36 L . V = . [V2 = 364 O Vi = 441, - V2 = 11L . From ideal ni = 1.90 moles n₂=? gas law we have Vzni 11 x 1,90 0.475 i 44 in z 27 = - V Ina=0.475 moles)