Question

A car starts from rest, and begins accelerating at a constant rate a1. It accelerates at this rate from a distance of 56.9 m from its starting point, and then immediately begins to decelerate at a different constant rate a2, eventually coming to rest again after traveling an additional distance of 79.4 m from where it began decelerating. the entire tripfrom start to finish(starting and ending at rest) lasts for a duration of 19.1 s.

a)what is the magnitude of the initial rate of acceleration, a1? (answer in m/s^2)

b)what is the magnitude of the subsequent rate of deceleration, a2?

c)what is the duration of the first part of the trip (the acceleration phase)? (answer in s)

d)what is the duration of the second part of the trip (the deceleration phase)? (answer in s)

e) what is the car's average speed over the course of the entire trip?(answer in m/s)

Answer 1

tte average Neletti., 26 MTha placament (s) , the tine (t) and he avexoge Uelect (Vava) are g elated as A he cas staruted U. dlurinq aecetetated motion ra.ta. 4st part 아肱emotic w s-56.9 accelerat m = a 2 56.9 ut

040 2×56.9 136.3 1a-1 -14. 3 m a) 143x 14.3 1.7Amls* 皂S

Ind patt 아 motion s= 79.4 m 14,3 x14. 3 2 x 79.4 O2 2 S 1.23 m]s negative gn indicatas de calsration

437.15 mls - 7.96 sec aji 14.3 7.15 m/s 7.15 average 8pen tra entre trip total olana 136.3 19-